2. log x = 3 + log x - log 10?
2. log x = 3 + log x - log 10.
2. log x = 3 + log x - log 10.
En resumen
2log x = 3 + log x - log 10 2 log x - log x = 3 - log 10 log x = 3 - 1 log x = 2 x = 10² x = 100.
Ingridlaloca04
2log x = 3 + log x - log 10
2 log x - log x = 3 - log 10
log x = 3 - 1
log x = 2
x = 10²
x = 100.
Tenemos : log125 = >2, 096910013 log 3125 = >3, 494850022 log 1 / 25 = > - 1, 397940009 log 1 / 625 = > - 2, 795880017 log 0. 20 = > - 0, 6989700043 log 0. 008 = > - 2, 096910013 espero ayude.
Camila, Vamos paso a paso Aplicando propiedades operatorias de logaritmos Los número negativos no tienen logaritmo x = 4 S = {4}.
✔PROPIEDAD : ✔OPERANDO : .
Log2 + log(x + 3) = log√2x log[2(x + 3)] = log√2x 2x + 6 = √2x (2x + 6)² = 2x 4x² + 24x + 36 = 2x 4x² + 24x - 2x + 36 = 0 4x² + 22x + 36 = 0 2x² + 11x + 18 = 0 Hasta hay me queda, esta bien el problema?