- 18 - [3(x + 2) + 4] = 21 - [6( - 2x - 2) + 1]?
- 18 - [3(x + 2) + 4] = 21 - [6( - 2x - 2) + 1].
0Luisgualan1
- 18 - [3(x + 2) + 4] = 21 - [6( - 2x - 2) + 1].
En resumen
- 18 - [3x + 6 + 4] = 21 - [ - 12x - 12 + 1] - 18 - [3x + 10] = 21 - [ - 12x - 11] - 18 - 3x - 10 = 21 + 12x + 11 - 28 - 3x = 32 + 12x - 28 - 32 = 12x + 3x - 60 = 15x x = - 60 / 15 x = - 4.
Yudithnaranjo18
- 18 - [3x + 6 + 4] = 21 - [ - 12x - 12 + 1] - 18 - [3x + 10] = 21 - [ - 12x - 11] - 18 - 3x - 10 = 21 + 12x + 11 - 28 - 3x = 32 + 12x - 28 - 32 = 12x + 3x - 60 = 15x
x = - 60 / 15
x = - 4.