A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2109 sq. M, then what is the width of the road? , ayuda porfa.
En resumen
Area of the park = (60 x 40) m2 = 2400 m2. Area of the lawn = 2109 m2. Area of the crossroads = (2400 - 2109) m2 = 291 m2. Let the width of the road be x metres. Then, 60x + 40x - x2 = 291x2 - 100x + 291 = 0(x - 97)(x - 3) = 0x = 3. The width of the road is 3 m.
Pequeñes
Area of the park = (60 x 40) m2 = 2400 m2.
Area of the lawn = 2109 m2.
Area of the crossroads = (2400 - 2109) m2 = 291 m2.
Let the width of the road be x metres.
Then, 60x + 40x - x2 = 291x2 - 100x + 291 = 0(x - 97)(x - 3) = 0x = 3.
The width of the road is 3 m.
El niño corre en el parque?
There aren't two children at the park.
A un lado del parque central y de la carniceria.
Respuesta : El encontró al niño en el parque. Explicación :