A cubic meter of soil in its natural state weighs 17. 75 kn ; after being dried it weighs 15. 08 kn. The specific gravity of the solids is 2. 70. determine the wáter content, void ratio, porosity and degree of saturation for the soil as existed in its natural state.
En resumen
The wáter content, void ratio, porosity and degree of saturation for the soil as existed in its natural state are : w = 17. 7% ; e = 0. 756 ; n = 0. 4 ; Sr = 0. 716 Given : W = 17. 75 KN → Wd = 15. 08 KN (when dried) Gs = 2. 70 V = 1 m³ w = ? E = ? N = ? Sr = ?
The wáter content, void ratio, porosity and degree of saturation for the soil as existed in its natural state are : w = 17.
7% ; e = 0.
756 ; n = 0.
4 ; Sr = 0.
716 Given : W = 17.
75 KN → Wd = 15.
08 KN (when dried) Gs = 2.
70 V = 1 m³ w = ?
E = ?
N = ?
Sr = ?
Volumen masa Air ( 1 - Sr) * e o water e Sr * e wGsρw Solid 1 Gsρw a) w = Mw / Ms w = ( 17.
75 - 15 .
08 ) / 15.
08 = 0.
177→ w = 17.
7% γ = Gs * (1 + w) γw / ( 1 + e) = W / V = 17.
75 / 1 = 17.
75 KN / m³ 17.
75 = 2.
70 * ( 1 + 0.
177 ) * 9.
81 / (1 + e) de donde : void ratio e = 0.
756 porosity : n = Vv / V = e / (1 + e) n = 0.
4 Sr = W * Gs / e = 0.
177 * 2.
70 / 0.
667 Sr = 0.
716.
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