Una piedra se lanza verticalmente hacia arriba y se eleva a una altura de 20 m ¿A qué velocidad fue lanzada? Necesito la formula y el procedimiento con sus unidades. Gracias.
En resumen
Vf² = Vo² * t±2 * g * h 0² = Vo² - 2(10)(20) 0 = Vo² - 400 400 = Vo² √400 = Vo 20 = Vo.
Vf² = Vo² * t±2 * g * h
0² = Vo² - 2(10)(20)
0 = Vo² - 400
400 = Vo²
√400 = Vo
20 = Vo.
Datos :
<img src="https://tex.z-dn.net/?f=%5Ctriangle%20Y%3D20m%5C%5C%0A%5C%5C%0Ag%3D9.8%5Cfrac%7Bm%7D%7Bs%5E2%7D%5C%5C%0A%5C%5C%0Avf%3D0%5C%3B%5C%3B%5C%3B%5C%3B%5C%3B%5C%3B%5C%3B%5C%3B%5C%3B%5CRightarrow%5C%3B%5C%3B%5C%3B%5C%3B%5C%3B%5C%3Bvelociad%5C%3Bfinal%5C%2Cen%5C%2Cla%5C%3Bmaxima%5C%2Caltura%5C%5C%0A%5C%5C%0A%5C%5C%0Avf%3Dvo-gt%5C%3B%5C%3B%5C%3B%5C%3B%5C%3B%5C%3B%5CRightarrow%5C%3B%5C%3B%5C%3B%5C%3B%5C%3B%5C%3Bdespejamos%5C%2Cvelociad%5C%2Cinicial%5C%2C%28vo%29%20%0A%5C%5C%0Avo%3Dgt%5C%5C%0A%5C%5C%0Avo%3D9.8t%5C%5C%0A%5C%5C%0A%5C%5C%0A%5Ctriangle%20Y%3Dvot-%5Cfrac%7B1%7D%7B2%7Dgt%5E2%5C%3B%5C%3B%5C%3B%5CRightarrow%5C%3B%5C%3B%5C%3By%5C%2Csabiendo%5C%2Cque%5C%2Cvelocidad%5C%2Cinical%5C%2Ces%5C%2C9.8t%5C%5C%0A%5C%5C%0A%5Ctriangle%20Y%3D9.8txt-%5Cfrac%7B1%7D%7B2%7Dgt%5E2%5C%5C%0A%5C%5C%0A%5Ctriangle%20y%3D9.8t%5E2-%5Cfrac%7B1%7D%7B2%7D9.8t%5E2%5C%5C%0A%5C%5C%0A20%3D9.8t%5E2-4.9t%5E2%5C%5C%0A%5C%5C%0A20%3D4.9t%5E2%5C%5C%0A%5C%5C%0At%3D%5Csqrt%7B%5Cfrac%7B20%7D%7B4.9%7D%7D%3D2.02s" />
<img src="https://tex.z-dn.net/?f=vo%3D9.8t%3D9.8%5Ctimes%202.02%5C%5C%0A%5C%5C%0Av0%3D%5Cbf%7B19.8%5Cfrac%7Bm%7D%7Bs%7D%7D" />.
V0 = velocidad inicial g gravedad y h altura v0 = raiz de 2gh v0 = raiz de 2×9. 8×20 v0 = 19. 80.
- 2gy = V" - Vo" (velocidad final = 0) y = ( - 100m / s) / ( - 2 * 10m / s") Y = 5m.