Un vehículo parte del reposo y en 2 min cambia su velocidad a 30 km / h calcular la aceleración y la distancia recorrida cuando han transcurrido 6 min . Movimiento uniformemente acelerado.
En resumen
Respuesta : JHKExplicación : NNJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJ.
Respuesta : JHKExplicación : NNJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJ.
Datos V = 0 D = 30 m Vf = 6m / s A = x T = x resolucion : d = (vi + vf). T 2.
Respuestas : aceleración ≈ 0, 55 m / s² tiempo ≈ 16, 22 s Te adjunto procedimiento.
Primeramente transformamos las unidades que tienen en otras para facilitar el cálculo tiempo(t) = 2min120s distancia(d) = 18km18000m te dice que parte del reposo entonces su velocidad inicial(Vo) vale 0 entonces usando…