Un movil de masa igual 120kg parte del reposo accionado por una fuerza constante igual 1, 6x10 ^ 3 durante 2 minutos a calcular la rapidez que lleva al cabo de ese tiempo b la distancia que rrecore?

<img src="https://tex.z-dn.net/?f=%5Ctextup%7BUsando%20la%20segunda%20ley%20de%20Newton%20se%20tiene%3A%7D%5C%5CF%3Dma%5C%5C%5Ctextup%7BDespejando%20la%20aceleraci%5C%27on%20a%20se%20tiene%3A%7D%5C%5Ca%3D%5Cfrac%7BF%7D%7Bm%7D%5C%5Ca%3D%5Cfrac%7B1.6%5Ctimes10%5E%7B3%7D%5C%2CN%7D%7B120%5C%2Ckg%7D%5C%5Ca%3D13.33%5C%2Cm%2Fs%5E%7B2%7D%5C%5C%5Ctextup%7BRecordando%20que%20el%20m%5C%27ovil%20parte%20del%20reposo%20y%20usando%20una%20de%20las%20ecuaciones%20b%5C%27asicas%20de%20la%20cinem%5C%27atica%20obtenemos%3A%7D%5C%5Cv_%7Bf%7D%3Dv_%7Bi%7D%2Bat%5C%5Cv_%7Bf%7D%3D0%2B%2813.33%5C%2Cm%2Fs%5E%7B2%7D%29%28120%5C%2Cs%29%5C%5Cv_%7Bf%7D%3D1600%5C%2Cm%2Fs%5C%5C%5Ctextup%7BFinalmente%20buscamos%20la%20distancia%20d%20y%20se%20obtiene%3A%7D%5C%5Cd%3Dv_%7Bi%7Dt%2B%5Cfrac%7Bat%5E%7B2%7D%7D%7B2%7D%5C%5Cd%3D0%2B%5Cfrac%7B%2813.33%5C%2Cm%2Fs%5E%7B2%7D%29%28120%5C%2Cs%29%5E%7B2%7D%7D%7B2%7D%5C%5Cd%3D95976%5C%2Cm" />

Saludos.