Hola, espero que me puedan ayudar lo antes posible, y explicarme el procedimiento?

SOLUCIÓN♛ HØlα!

✌ Primero analizaremos cuando le aplicamos una fuerza F, realizaremos el diagrama de cuerpo libre para cada bloque teniendo en cuenta las siguientes observaciones✽ Descompusimos el peso de m2 y m1 en el eje "x" e "y"✽ Como hay una cuerda existe tensión(T)✽ Las reacciones del piso sobre los bloques no generarán movimiento ya que nuestro sistema solo se mueve en "x" mas no en "y" ✽ Para este caso la aceleración será cero(a = 0) ya que se mueve con velocidad constante ☞ Aplicamos 2da Ley de Newton para m2 <img src="https://tex.z-dn.net/?f=%5Csum%20F_%7Bx%7D%3Dma%5C%5C%5C%5CT%20-%20W_%7B2%7D%5Csin%2830%5C%C2%B0%29%3Dm_2%280%29%5C%5C%5C%5CT%20-%20W_%7B2%7D%5Csin%2830%5C%C2%B0%29%3D0%5C%5C%5C%5C%5Cboxed%7BT%20%3D%20W_%7B2%7D%5Csin%2830%5C%C2%B0%29%7D" />☞ Aplicamos la 2da Ley de Newton para m1 <img src="https://tex.z-dn.net/?f=%5Csum%20F_%7Bx%7D%3Dma%5C%5C%5C%5CF%20-%20W_%7B1%7D%5Csin%2830%5C%C2%B0%29-T%3Dm_1%280%29%5C%5C%5C%5CF%20-%20W_%7B1%7D%5Csin%2830%5C%C2%B0%29-T%3D0%5C%5C%5C%5CF%20%3D%20W_%7B1%7D%5Csin%2830%5C%C2%B0%29%2BT%5C%5C%5C%5C%5Cmathrm%7BReemplazamos%20%5C%3AT%7D%5C%5C%5C%5CF%20%3D%20W_%7B1%7D%5Csin%2830%5C%C2%B0%29%2BW_%7B2%7D%5Csin%2830%5C%C2%B0%29%5C%5C%5C%5C%5Cboxed%7B%5Cboldsymbol%7BF%3D%20m_%7B1%7Dg%5Csin%2830%5C%C2%B0%29%2Bm_%7B2%7Dg%5Csin%2830%5C%C2%B0%29%7D%7D" />Ahora analicemos cuando le aplicamos la fuerza de 3F, en este caso ya existirá aceleración, el diagrama de cuerpo libre esta en la figura 2, entonces➺ Aplicamos la 2da Ley de Newton para m2 <img src="https://tex.z-dn.net/?f=%5Csum%20F_%7Bx%7D%3Dma%5C%5C%5C%5CT%20-%20W_%7B2%7D%5Csin%2830%5C%C2%B0%29%3Dm_2%20a%5C%5C%5C%5C%5Cboxed%7BT%20%3D%20W_%7B2%7D%5Csin%2830%5C%C2%B0%29%2Bm_2%20a%7D" />➺ Aplicamos la 2da Ley de Newton para m1 <img src="https://tex.z-dn.net/?f=%5Csum%20F_%7Bx%7D%3Dma%5C%5C%5C%5C3F%20-%20W_%7B1%7D%5Csin%2830%5C%C2%B0%29-T%3Dm_1%20a%5C%5C%5C%5C%5Cmathrm%7BReemplazamos%20%5C%3AT%7D%5C%5C%5C%5C3F%20-%20W_%7B1%7D%5Csin%2830%5C%C2%B0%29-W_%7B2%7D%5Csin%2830%5C%C2%B0%29-m_2%20a%3Dm_1%20a%5C%5C%5C%5C3F%20%3Dm_1%20a%2B%20m_2a%2BW_%7B1%7D%5Csin%2830%5C%C2%B0%29%2BW_%7B2%7D%5Csin%2830%5C%C2%B0%29%5C%5C%5C%5C3F%20%3Dm_1%20a%2B%20m_2a%2Bm_%7B1%7Dg%5Csin%2830%5C%C2%B0%29%2Bm_%7B2%7Dg%5Csin%2830%5C%C2%B0%29%5C%5C%5C%5C%5Cboxed%7B%5Cboldsymbol%7BF%3D%5Cdfrac%7Bm_1%20a%2B%20m_2a%2Bm_%7B1%7Dg%5Csin%2830%5C%C2%B0%29%2Bm_%7B2%7Dg%5Csin%2830%5C%C2%B0%29%7D%7B3%7D%7D%7D" />Igualaremos F<img src="https://tex.z-dn.net/?f=m_%7B1%7Dg%5Csin%2830%5C%C2%B0%29%2Bm_%7B2%7Dg%5Csin%2830%5C%C2%B0%29%20%3D%20%5Cdfrac%7Bm_1%20a%2B%20m_2a%2Bm_%7B1%7Dg%5Csin%2830%5C%C2%B0%29%2Bm_%7B2%7Dg%5Csin%2830%5C%C2%B0%29%7D%7B3%7D%5C%5C%5C%5C%5C%5C3%28m_%7B1%7Dg%5Csin%2830%5C%C2%B0%29%2Bm_%7B2%7Dg%5Csin%2830%5C%C2%B0%29%20%29%3D%20m_1%20a%2B%20m_2a%2Bm_%7B1%7Dg%5Csin%2830%5C%C2%B0%29%2Bm_%7B2%7Dg%5Csin%2830%5C%C2%B0%29%5C%5C%5C%5C%5C%5C3m_%7B1%7Dg%5Csin%2830%5C%C2%B0%29%2B3m_%7B2%7Dg%5Csin%2830%5C%C2%B0%29%3D%20m_1%20a%2B%20m_2a%2Bm_%7B1%7Dg%5Csin%2830%5C%C2%B0%29%2Bm_%7B2%7Dg%5Csin%2830%5C%C2%B0%29%5C%5C%5C%5C%5C%5C2m_%7B1%7Dg%5Csin%2830%5C%C2%B0%29%2B2m_%7B2%7Dg%5Csin%2830%5C%C2%B0%29%3D%20m_1%20a%2B%20m_2a%5C%5C%5C%5C%5C%5C2m_%7B1%7Dg%5Csin%2830%5C%C2%B0%29%2B2m_%7B2%7Dg%5Csin%2830%5C%C2%B0%29%3D%20%28m_1%2B%20m_2%29a%5C%5C%5C%5C%5C%5Ca%20%3D%20%5Cdfrac%7B2m_%7B1%7Dg%5Csin%2830%5C%C2%B0%29%2B2m_%7B2%7Dg%5Csin%2830%5C%C2%B0%29%7D%7Bm_1%2B%20m_2%7D%5C%5C%5C%5C%5C%5C%5Cmathrm%7BSabemos%5C%3Aque%5C%3Am_1%3D1kg%5C%3Ay%5C%3Am_%7B2%7D%20%3D2kg%7D" /><img src="https://tex.z-dn.net/?f=a%20%3D%20%5Cdfrac%7B2%281%29%28g%29%5Csin%2830%5C%C2%B0%29%2B2%282%29%28g%29%5Csin%2830%5C%C2%B0%29%7D%7B1%2B%202%7D%5C%5C%5C%5C%5Cboxed%7B%5Cboxed%7B%5Cboldsymbol%7Ba%3Dg%7D%7D%7D" />OBS.

Si el signo hubiese sido negativo el movimiento era sentido contrario.

Hallemos la tensión <img src="https://tex.z-dn.net/?f=T%20%3D%20W_%7B2%7D%5Csin%2830%5C%C2%B0%29%2Bm_2%20a%5C%5C%5C%5CT%20%3D%20m_%7B2%7Dg%5Csin%2830%5C%C2%B0%29%2Bm_2%28g%29%5C%5C%5C%5CT%20%3D%202%2810%29%28%5Csin%2830%5C%C2%B0%29%29%2B2%2810%29%5C%5C%5C%5CT%20%3D%2020%5C%3AN" />.