A cyclist travels a distance of 1200 m due north before going 2000 m due east followed by 500 m south - west. Draw a scale diagram to calculate the. Com cyclist's final displacement from her initial position.
En resumen
D1 = 1200m North d2 = 2000 m East d3 = 500 m south - west Draw a scale diagram to calculate the. Com cyclist's final displacement from her initial position = ? Solution : summation of forces on the x - axis : drx = d2 - d3x drx = 2000m - 500m * cos 45º drx = 1646.
D1 = 1200m North d2 = 2000 m East d3 = 500 m south - west Draw a scale diagram to calculate the.
Com cyclist's final displacement from her initial position = ?
Solution : summation of forces on the x - axis : drx = d2 - d3x drx = 2000m - 500m * cos 45º drx = 1646.
446 m summation of forces n the y - axis : dry = d1 - d3 * sen 45º dry = 1200 m - 500 m * sen45º dry = 846.
446 m .
Dr = 1646.
446 i + 846.
446 j m dr = √( 1646.
446 m)² + ( 846.
446 m)² dr = 1851.
28 m module tangα = dry / drx = 846.
446 / 1646.
446 α = 27.
20º direction.
1. - the distance is 3km because 1km + 1km + 1km = 3km2. - the displacement is √5.
Yo también se inglés pero no entiendo un c4r4jo lo que dices.