Dada la función f(x) = 2x ^ 2 - 3x,Hallar f( - 2) =f(0) =f(a + 1) =?
Dada la función f(x) = 2x ^ 2 - 3x, Hallar f( - 2) = f(0) = f(a + 1) =.
Mejor respuesta
2
F(x) = 2x² - 3x
f( - 2) = 2x² - 3x
f( - 2) = 2( - 2)² - 3( - 2)
f( - 2) = 2(4) + 6
f( - 2) = 8 + 6
f( - 2) = 14
f(0) = 2x² - 3x
f(0) = 2(0)² - 3(0)
f(0) = 2(0) - 0
f(0) = 0
f(a + 1) = 2x² - 3x
f(a + 1) = 2(a + 1)² - 3(a + 1)
f(a + 1) = 2(a² + 2a + 1) - 3a - 3
f(a + 1) = 2a² + 4a + 2 - 3a - 3
f(a + 1) = 2a² + a - 1
Saludos!