Solucionar las ecuaciones :2(x - 5) = 3(x - 2)5(y + 7) - 3(y + 2) = 04(x + 1) + 2(2x + 6) = 3?
Solucionar las ecuaciones : 2(x - 5) = 3(x - 2) 5(y + 7) - 3(y + 2) = 0 4(x + 1) + 2(2x + 6) = 3.
Solucionar las ecuaciones : 2(x - 5) = 3(x - 2) 5(y + 7) - 3(y + 2) = 0 4(x + 1) + 2(2x + 6) = 3.
ax² + bx + c = 0
Pregunta de Baldor · 1 respuesta · 10 votos · mejor respuesta de Damarismartinez123
En resumen
2(x - 5) = 3 (x - 2) 2x - 10 = 3x - 6 - 10 + 6 = 3x - 2x - 4 = 1x 1 ÷ 4 = x 4 = x 4(x + 1) + 2(2x + 6) = 3 4x + 1 + 4x + 6 = 3 4x + 4x = + 3 - 1 - 6 8x = - 4 x = - 4 ÷ 8 x = - 2.
2(x - 5) = 3 (x - 2)
2x - 10 = 3x - 6 - 10 + 6 = 3x - 2x - 4 = 1x
1 ÷ 4 = x
4 = x
4(x + 1) + 2(2x + 6) = 3
4x + 1 + 4x + 6 = 3
4x + 4x = + 3 - 1 - 6 8x = - 4 x = - 4 ÷ 8 x = - 2.
2(x - 5) = 3 (x - 2) 2x - 10 = 3x - 6 - 10 + 6 = 3x - 2x - 4 = 1x 1 ÷ 4 = x 4 = x 4(x + 1) + 2(2x + 6) = 3 4x + 1 + 4x + 6 = 3 4x + 4x = + 3 - 1 - 6 8x = - 4 x = - 4 ÷ 8 x = - 2.